My initial thought was that it's surprising that the engineer is using i whereas the mathematician is using j. But I know some engineers who are hardcore in favour of i. No mathematicians who prefer j though. So if such an engineer were dating a mathematician of all people who used j, I could see that being ♠ .
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Fake and gay.
No way the engineer corrects the mathematician for using j instead of i.
Wait bottom mathematican is using j=√-1 instead of i and not the engineer? Because I'm EE gang, and all my homies use j.
That part also got me really confused. All the mathematicans I know use i while engineers use i or j depending on the kind of engineer. I've never seen a Pikachu engineer using anything other than j.
The fun starts when you study quaternions
i^2 = j^2 = k^2 = ijk = −1
This can't be real
They're actually very useful: https://en.wikipedia.org/wiki/Quaternion
(...I think you may have gotten whooshed...)
Hehe, maybe a little, but wanted to share just in case someone didn't know :3
I clicked your link, I barely made it out of highschool so I have no idea what any of it means, but I like reading things I shouldn't understand anyway, sometines it's so interesting even without understanding.
So I thank you!
Quaternions are the closest we get to lovecraftian horror in real life.
Four dimensional and mostly imaginary, they were carved into a stone bridge by a crazy mathematician in a fit of madness, Lord Kelvin called them "unmixed evil", and the Mad Hatter from Alice may have been inspired by them.
Also they have been a curiosity at best for a long time, despite the efforts of a secret Quaternion Society, but they suddenly blew up in usefulness in modern times as they happen to be an easy and fast way for computers to describe rotations in 3D space, so they're everywhere.
Yeah, lovecraftian as shit.
It gets worse actually. You can define a number system using any power of 2 amount of i-like units in a similar relationship to quaternions using the Cayley-Dickson construction
Fascinatingly, you lose some property of the algebra at each step. Quaternions aren't commutative: ABC != CBA. Octonians aren't associative: (AB)C != A(BC). Once you get into 16 i's with subscripts, it really gets crazy.
(Also, I just got the joke. Damnit @HappyFrog@lemmy.blahaj.zone your serious answer threw me off!)
[Lapsed] mechanical engineering gang checking in. I was also surprised. Though, tbh, I think it came down to personal preference of the professor more than field-wide consensus.
sado-mathochist
NGL, this is hot.
operative?
Also mathematicians use i for imaginary, engineers use j. The story does not add up. I have never seen a single mathematician use j for imaginary.
As an EE, I used both. Def not a mathematician though. Fuck that, I just plug variables into programs now.
Engineer here: mostly use i, but have seen j used plenty. First time I saw j used was by a maths professor.
Interesting I never saw j from a maths person. Friends (from a decade ago!) in electronics eng dep said they use j because i was reserved for current. perhaps the latter depends on the department.
j is pretention when a math doer does it. j is for engineers and you don't even understand the bubble ratio filtering equation let alone be asking to envision what temp you did the mAEth in.
You got lost in the number of letters instead of realizing the MeTowel's important presence til that EOTU moment of that manufa turing of Big Black Goles you get to watch it all happen again as Thanos facepalms.

Is anyone doing anything tonight?
Something something distance calls for norm, not just squares.
||i||² + ||1||² = 2
Imagining your death. :P
But seriously, it's perfectly sensible when remember that i is just the mathematical representation of "left turn", just like -1 is the mathematical representation of "go backwards"-- and as we know, two left turns sends you backwards. So think about this triangle in the following way:
Imagine you are a snail, starting at the origin. Now imagine that you walk forward 1 step along the horizontal line. Then you turn 90° to the left to start walking along the vertical line, but then, because you need to walk i steps along this line you take another 90° turn to the left, which means that you are now walking backwards and you end up back at the origin. How far away from the origin are you? Zero steps.
This is the kind of brat I can get behind. 😏
As a physicist I can't understand why would anyone complain about a +jb or $\int dx f(x)$. Probably because we don't fuck
As a software dude I can see you wrote a regex, I just can't find out what you're trying to match.
Heeyy... So when you need to express something more, well, delicate than just code, you need to use math symbols. For that you can use tex expressions. Modern markdown supports it: just copy and paste the $..$ part into any render engine
Pardon my denseness, but is this sarcasm? Since that is a TeX snippet.
Why would a RegEx start with a $?
Better plot than 50 Shades of Grey
Why would a mathematician use j for imaginary numbers and why would engineer be mad at them?
The only thing I can think of is that the OP studied electrical engineering at some point. But it's a 4chan story so probably fake anyway.
I think it might be the wrong way around: Engineers like to use j for imaginary numbers because i is needed for current.
Mathematicians are taught to be elastic with notation, because they tend to be taught many different interpretations of the same theory.
On the other hand engineers use more strict and consistent notation, their classes have a more practical approach.
Using the same notation makes it faster to read and apply math, a more agile approach helps with learning new theories and approaches and with being creative.
Me, a language/arts person: "Huh?"
I love how that wannabe 4chan nerd just got outnerded in the comment section
I think rather d/dx is the operator. You apply it to an expression to bind free occurrences of x in that expression. For example, dx²/dx is best understood as d/dx (x²). The notation would be clear if you implement calculus in a program.
If not fraction, why fraction shaped?
I just think of the definition of a derivative.
d is just an infinitesimally small delta. So dy/dx is literally just lim (∆ -> 0) ∆y/∆x.
which is the same as lim (x_1 -> x_0) [f(x_0) - f(x_1)] / [x_0 - x_1].
Note: ∆ -> 0 isn't standard notation. But writing ∆x -> 0 requires another step of thinking: y = f(x) therefore ∆y = ∆f(x) = f(x + ∆x) - f(x) so you only need ∆x approaching zero. But I prefer thinking d = lim (∆ -> 0) ∆.
$\int dx f(x)$ is standard notation for physicists
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