Science Memes

hideshow 20 child comments

parent

[–] SmartmanApps@programming.dev 0 points 10 months ago (19 children)

Illiterate fraud

says person who thinks "means" and "equals" mean the same thing 😂

hideshow 19 child comments

parent

[–] mindbleach@sh.itjust.works 0 points 10 months ago (18 children)

By all means, humiliate yourself by splitting that hair.

hideshow 18 child comments

parent

[–] SmartmanApps@programming.dev 0 points 10 months ago (17 children)

By all means, humiliate yourself by splitting that hair

I'll take that as an admission that you're wrong then, given you can't defend your wrong interpretation of it (which you would know is wrong if you had read more than 1 paragraph of the book!) 😂

hideshow 17 child comments

parent

[–] mindbleach@sh.itjust.works 1 point 10 months ago (16 children)

This is you admitting there's no difference. You insist they're not the same. How?

hideshow 16 child comments

parent

[–] SmartmanApps@programming.dev -1 points 10 months ago (15 children)

You insist they’re not the same. How?

Not difficult, I already did in another post. If a=2 and b=3...

1/ab=1/(axb)=1/(2x3)=1/6

1/axb=1/2x3=3/2=1.5

hideshow 15 child comments

parent

[–] mindbleach@sh.itjust.works 1 point 10 months ago* (14 children)

That's convention for notation, not a distinction between a*b and ab both being the product of a and b.

You have to slap 1/ in front of things and pretend that's the subject, to avoid these textbooks telling you, ab means a*b. They are the same thing. They are one term.

hideshow 14 child comments

parent

[–] SmartmanApps@programming.dev 0 points 10 months ago (13 children)

That’s convention for notation

Nope, still rules

not a distinction between a*b and ab

says person who only read 2 sentences out of the book, the book which proves the statement wrong 😂

a*b and ab both being the product of a and b

Nope, only ab is the product, and you would already know that if you had read more than 2 sentences 😂

You have to slap 1/ in front of things and pretend that’s the subject

"identically equal", which you claimed it means, means it will give the same answer regardless of what's put in front of it. You claimed it was identical, I proved it wasn't.

avoid these textbooks telling you

It kills you actually, but you didn't read any of the parts which prove you are wrong 🙄just cherry pick a couple of sentences out of a whole chapter about order of operations 🙄

They are the same thing. They are one term

Nope! If they were both 1 term then they would give the same answer 🙄

1/ab=1/(axb)=1/(2x3)=1/6

1/axb=1/2x3=3/2=1.5

Welcome to why axb is not listed as a Term on Page 37, which if you had read all the pages up until that point, you would understand why it's not 1 Term 🙄

hideshow 13 child comments

parent

[–] mindbleach@sh.itjust.works 0 points 10 months ago* (12 children)

'If a+b equals b+a, why is 1/a+b different from 1/b+a?'

ab means a*b.

That's why 1/ab=1/(a*b).

But we could just as easily say 1/ab = (1/a)*b, because that distinction is only convention.

None of which excuses your horseshit belief that a(b)^2^ occasionally means (ab)^2^.

hideshow 12 child comments

parent

[–] SmartmanApps@programming.dev 0 points 10 months ago (11 children)

‘If a+b equals b+a, why is 1/a+b different from 1/b+a?’

Because they're not identically equal 🙄 Welcome to you almost getting the point

ab means a*b

means, isn't equal

That’s why 1/ab=1/(a*b)

Nope, it's because ab==(axb) <== note the brackets duuuhhh!!! 😂

But we could just as easily say 1/ab = (1/a)*b

No you can't! 😂

because that distinction is only convention

Nope! An actual rule, as found not only in Maths textbooks (see above), but in all textbooks - Physics, Engineering, Chemistry, etc. - they all obey ab==(axb)

None of which excuses your horseshit belief that a(b)2

says person still ignoring all these textbooks

hideshow 11 child comments

parent

[–] mindbleach@sh.itjust.works 0 points 10 months ago* (10 children)

No you can’t!

Yes we could, because it's a theoretical different notation. Mathematics itself does not break down, if you have to put add explicit brackets to 1/(ab).

Mathematics does break down when you insist a(b)^2^ gets an a^2^ term, for certain values of b. It's why you've had to invent exceptions to your made-up bullshit, and pretend 2(8)^2^ gets different answers when simplified from 2(5+3)^2^ versus 2(8*1)^2^.

hideshow 10 child comments

parent

[–] SmartmanApps@programming.dev 0 points 10 months ago (9 children)

Yes we could

No you can't! 😂

it’s a theoretical different notation

In other words against the rules of Maths that we have, got it

does not break down, if you have to put add explicit brackets to 1/(ab)

But it does breakdown if you treat ab as axb 🙄

if you have to put add explicit brackets to 1/(ab)

We explicitly don't have to, because brackets not being needed around a single Term is another explicit rule of Maths, 🙄 being the way everything was written before we started using Brackets in Maths. We wrote things like aa/bb without brackets for many centuries. i.e. they were added on after we had already defined all these other rules centuries before

Mathematics does break down when you insist a(b)2 gets an a2 term

No it doesn't. If you meant ab², then you would just write ab². If you've written a(b)², then you mean (axb)²

for certain values of b

Got nothing to do with the values of b

It’s why you’ve had to invent exceptions to your made-up bullshit

says person still ignoring all these textbooks

pretend 2(8)2

There's no pretending, It's there in the textbooks

when simplified from 2(5+3)2 versus 2(8*1)2

You know it's called The Distributive Property of Multiplication over additon, right? And that there's no such thing as The Distributive Property of Multiplication over Multiplication, right? You're just rehashing your old rubbish now

hideshow 9 child comments

parent

[–] FishFace@piefed.social 1 point 10 months ago (3 children)

Couldn't resist:

but when multiplications are denoted by juxtaposition, as in 4c ÷ 3ab

Damn, and I thought they were called "products" not "multiplications" 🤔🤔🤔

No it doesn’t. If you meant ab², then you would just write ab². If you’ve written a(b)², then you mean (a×b)²

If you can find an explicit textbook example where writing a(b)² is said to be evaluated as (a×b)² then that's another way you can prove your good faith (When I say "explicit" I don't mean it must literally be that formula; the variables a and b could have different names, or could be constants written with numerals, and the exponent could be anything other than 1). Likewise, if you can find any explicit textbook example which specifically mentions an "exception" to the distributive law, that would demonstrate good faith.

I'm not saying that such an explicit example is the only way to demonstrate your claim, but I'm just trying to give you more opportunities to prove that you're not just a troll and that it's possible to have a productive discussion. You insist you're talking about mathematical rules that cannot be violated, so it should be no problem to find an explicit mention of them.

If you think this insistence on demonstrating your good faith is unfair, you should remember that you are saying that the practice of calculators, mathematical tools, programming languages and mathematical software are all wrong and that you are right, and that my interpretation of your own textbooks is wrong. While it's not impossible for many people to be wrong about something and for me to interpret something wrong, if you show no ability to admit error, or to admit that disagreement from competing authorities casts doubt on your claims, or to evince your controversial claims with explicit examples that are not subject to interpretational contortions, the likelihood is that you're not willing to ever see truth and there's no point arguing with such a person.

By the way, sorry for making multiple replies on the same point.

As my own show of good faith, I do see that one of your textbooks (Chrystal) has the convention that a number "carries with it" a + or -, which is suppressed in the case of a term-initial positive number. If you demonstrate it worth continuing the discussion, I'll explain why I think this is a bad convention and why the formal first-order language of arithmetic doesn't have this convention.

hideshow 3 child comments

parent

[–] mindbleach@sh.itjust.works 1 point 10 months ago (2 children)

If you’ve written a(b)², then you mean (a×b)²

When shown a textbook that explicitly distinguishes 6(ab)^3^ meaning 6(ab)(ab)(ab) and (6ab)^3^ meaning (6ab)(6ab)(6ab), they accidentally got it right whilst sneering and inventing their sPeCiAl cAsE:

6a²b²=6(ab)²

They can't even keep their horseshit straight when their inane pivots to division are directly addressed. Every response begins "nuh uh!" and backfills whatever needs to be true for you to be wrong and them to be smarterer.

They're just full of shit.

hideshow 2 child comments

parent

[–] FishFace@piefed.social 1 point 10 months ago (1 child)

I haven't been able to follow the entirety of that conversation so I don't remember what exactly he said about combining (implicit) multiplication, brackets and powers.

I think their fundamental confusion is in thinking that the distributive law is something you must do instead of a property of multiplication that you can use to aid in the manipulation of algebraic expressions but don't have to. Folded into their inability to understand that some aspects of maths are custom and convention, whilst others are rules fundamental to the operation of the universe. Somewhere along the way he seems to think that distributivity is something to do with brackets instead of something to do with addition and multiplication - I really don't understand how that has happened!

I'm pursuing a tack where I'll see if I can get him to actually cop to any of his verifiable mistakes, or back up any of his whackadoodle claims with direct references. If he can't, I'm out - but I do like to give people an opportunity to demonstrate they're not trolling. The nice thing is that it doesn't really matter whether they're trolling or not - someone who is able to admit mistakes is someone worth trying to convince they've made a mistake, and someone who isn't is not. So if you can test the waters with a simple mistake, even if it's not central, you can establish whether there's any point persevering.

Tomorrow I'm expecting another wall of text responding to every single word except the ones where I ask for such an admission, and I'll have satisfied myself he's a lost cause. I'll try and watch out for his spam on future arithmetic-ragebait threads so I can help the effort to head him off though :P

BTW did you go on his mastodon profile? He's had a bee in his bonnet about this, and been pushing his wrong ideas of what the distributive law are, since 2023.

parent

hideshow 1 child comment

[–] mindbleach@sh.itjust.works 2 points 10 months ago*

Oh yeah, had a laugh at some RPN guy saying, 'Hey you should check this thesis specifically about order of operations.'

This dipshit: "I already know what it'll be - a University person who's forgotten about Terms and The Distributive Law - they're ALL like that."

All of them! Wow! What a coincidence!

Isn't it fucking crazy how everyone in the world is wrong about this, and math still works?

parent

[–] mindbleach@sh.itjust.works 1 point 10 months ago (4 children)

So when you sneer that rules and notation are different, you don't know what those words mean.

Or you're so devoid of internality that when someone says 'imagine a different notation,' you literally can't.

There’s no pretending, It’s there in the textbooks

Show me any textbook that gets the answers you insist on. Show me one textbook where a(b+c)^2^ squares a.

hideshow 4 child comments

parent

[–] SmartmanApps@programming.dev -1 points 10 months ago (2 children)

P.S. show me where the squared is in...

you know, the actual topic, which you're trying to avoid because you know you are wrong

hideshow 2 child comments

parent

[–] mindbleach@sh.itjust.works 1 point 10 months ago (1 child)

Fuck where this started - you're here now, saying 2(8)^2^ is anything but 128. You're that wrong about basic fucking algebra, whilst sneering at everyone else.

Here's four textbooks across two centuries where a(b+c)^x^ is not (ac+bc)^x^.

parent

hideshow 1 child comment

[–] SmartmanApps@programming.dev 0 points 10 months ago

Fuck where this started

I'll take that as an admission that you're wrong. Thanks for playing

parent

[–] SmartmanApps@programming.dev -1 points 10 months ago

So when you sneer that rules and notation are different, you don’t know what those words mean

says the actual person who doesn't know what they mean 😂

when someone says ‘imagine a different notation,’ you literally can’t

Yes, you literally can't go rewriting all the rules of Maths that we've had for centuries just because you randomly want to do something different now that we've decided to add Brackets to it 😂 Your whole argument is based on pretending that all the rules of Maths were all written at the same time 🤣🤣🤣

Show me any textbook that gets the answers you insist on

Pick any of them which show a(b+c)=(ab+ac) 🙄