A gun tackle has a single pulley in both the fixed and moving blocks with 2 rope parts dividing the load of 100N. The mechanical advantage is 2, requiring a force of only 50N to lift the load.

Author: César Rincón

CC BY-SA 3.0

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[–] 2 points 4 months ago (9 children)

What's the force in this point?

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  • [–] 9 points 4 months ago (4 children)

    Somewhere between 100-150 N of downward force, depends on the angle that the rope on the left is being pulled at

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  • [–] 4 points 4 months ago (1 child)

    I don't think it can get as low as 100N, for that you would have to pull completely upwards. The shadow in the image implies a ceiling, so ~112N if we take 90° as the max angle. The 150N would be the only case with a completely downward force, if you pull at another angle the resulting force vector will be angled as well.

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  • [–] 1 point 4 months ago* (1 child)

    Wouldn't it depend on how fast that rope is pulled too, adding in the acceleration of the mass (or are you considering that with your range of 100-150)?

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  • [–] 3 points 4 months ago

    Nope. Right now the system is balanced, the rope is not being pulled just hold. To pull the weight up you need more than 50N, plus a bit more if we take into consideration the friction in the pulleys and in the rope itself.

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  • [–] 1 point 4 months ago (2 children)

    It should be 50 N assuming ideal system (0 pulley traction), right? What about non-ideal systems?

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  • [–] 2 points 4 months ago (1 child)

    Wouldn't it be 100, same as the mass being lifted (well more really, depending on the acceleration of that mass)?

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  • [–] 1 point 4 months ago

    No, the other commenters are right — it's between 100 and 150 depending on the angle. And it's like this because we have 50 N + 50 N on both sides of the top pulley (classic pulley thing) + 50 N more attached to it at the bottom. Kinda confusing at first, not gonna lie :)

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