A few months ago, I asked for advice - or I was simply bragging - about cutting the wires of a PC chassi fan, connecting them to a USB wire and thus being able to power the fan with one of my laptop's USB ports. Then, as if sent by the heavens, @onomatopoeia@lemmy.cafe said:

If you can, swap out the tape for some heat-shrink tubing. It’s cheap and does a much better job.
I immediately bought a heating gun (?) and heat shrink tubes. Since then, I have been exclusively using that method. It rocks. Today, I bought my first ever digital photo frame, the KD10FR-W. It's some old relic from ten or so years ago, possibly released in 2017 (sources needed). It's a Japanese product that I found at one of my local thrift stores in Sweden. HOW. WHY. Anyway, since it only came with a Japanese plug, I did the thing, and now, it would seem, Bob is my uncle. Nay, blood relative. Wait... Is that the same thing?

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Question/conversation time:

  1. The specs of the frame say: 5V==1500mA. I assume this means "minimum 5V, maximum 1500mA"? How else is my TV's 5V==900mA USB port powering it?
  2. What knowledge or skill have YOU picked up on the Fediverse that you use today? 😊
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[–] 7 points 2 months ago (3 children)
  1. The voltage has to be pretty close. You cant go significantly higher or lower. But the current is generally a max value. Its possible that if you cranked up the screen brightness it might need the full 1.5A. Also possible that your TV can actually provide more than 900mA.

  2. Dunno, would have to think harder. Will edit and update if I think of something.

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  • [–] [S] 2 points 2 months ago (2 children)

    Thanks! I hate that as a "commoner" I don't know better. 😅 I wish there was a more straightforward "yes/no" answer to this, such as: the V and A values on an end device is what you are allowed to pump into it AT MOST, and the V and A values on a power supply is what the power supply is able to pump out AT MOST. But, alas... Thanks again! 😊

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