5
Is it possible to cause undefined behaviour with static mut inside a function? (anarchist.nexus)
submitted 11 months ago by to c/rust@programming.dev
7 comments fedilink hide all child comments
 

For example, is there any problems with doing this?

fn main() {  
	static mut BUF: [u8; 0x400] = [0; 0x400];  
	let buf = &mut unsafe { BUF };  
}

and is this code the same as just using an array directly? From my understanding local variables get put on the stack but do the static variables do too?

I'm essentially trying to find the most performant way to get a simple read/write buffer.

you are viewing a single comment's thread
view the rest of the comments
[–] [S] 1 point 11 months ago (1 child)

My logic was simply: I need a buffer that is only initialised once no matter how many times the function is called. statics are initialised at program start so they seemed like a good fit. and since I wasn't planning for the function to me called multiple times simultaneously it seemed like the UB didn't matter. (which I think was correct)

  • permalink
  • fedilink
  • source
  • parent
  • hideshow 1 child comment
    •