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[–] 59 points 9 months ago (5 children)

the path of least resistance for the current would be down one connected bolt, then around the top plate, and up the other battery connected bolt, never down the pole, so the ceiling/floor gets heated up, possibly burn

note: those bolts must be supper long to go from ceiling to floor

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  • [–] 14 points 9 months ago (3 children)

    12v is hardly anything. This is not a joke, go put your hands on both terminals of a car battery. You won’t feel a thing.

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  • [–] 9 points 9 months ago*

    still can spin a big truck and/or turn on incandescent bulbs with temperatures in the thousands of degrees

    the internal resistance of lead-acid batteries is in the tens of mili-Ω, the circuit of 2 cables, 2 bolts and one plate/top of the pole would be in the low 100s mili-Ω. lets round up to 200mΩ, power = V•I = V^2/R = 12^2/0.2 = 720W, enough to heat up the top assembly of the pole, and smolder some wood

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